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【Example of prediction】 Calculate vapor-liquid equilibria for Methanol + Water + CaCl2 ( 4 mole % ) system at 1 atm by Solvation method when liquid composition of methanol is 60 mole % at salt free basis and solvation number of CaCl2 to methanol is 15.395 and that to water 18.7844. 【Solution】 From the given liquid compositions xi'= 0.6, xsalt= 0.04, xtotal,solvent= 0.96 then compositions at salt basis are calculated as x1= 0.6・0.96 = 0.576, x2= 0.4・0.96 = 0.384, respectively. Solvation number for each volatile component is given as S10 = 15.395, S20 = 18.7844 therefore, from relation; Si = Sio×xi' they are estimated as S1= 15.395・0.6 = 9.237, S2= 18.7844・0.4 = 7.514, respectively. Next, effective liquid compositions of each volatile component is from Eq. (4) calculated as x1a' = (0.576 - 9.237・0.04) / (1- 0.04 - 9.237・0.04 - 7.514・0.04) = 0.7122 Similarly x2a' = 0.2878.
Activity coefficients g1' and g2' for effective liquid compositions: x1a', x2a' are calculated by Wilson equation, using the following parameters for methanol + water system: Λ12 = 0.5515 and Λ21 = 0.8978. By applying Wilson equation: ln g1' = -ln (x1a' + Λ12 x2a') + x2a' [Λ12 / ( x1a' +Λ12 x2a') -Λ21 / (Λ21x1a' + x2a')] ln g2' = -ln (x2a' + Λ21 x1a') - x1a' [Λ12 / ( x1a' +Λ12 x2a') -Λ21 / (Λ21x1a' + x2a')] to the composions: x1a' and x2a' , we get ln g1'= 0.0418, ln g2' = 0.3142 then g1' = 1.0427, g 2' = 1.3692.
Second, activity coefficient for vapor pressure lowering gmix,solvent is determined. From solvation number for each pure solvent S10, S20, activity coefficients for respective component: g 1,solvent and g2, solvent are esimated by Eq. (2). g 1,solvent = (0.96 - 0.04・15.395) / (1 - 0.04・15.395) / 0.96 = 0.9332 g2, solvent = (0.96 - 0.04・15.395) / (1- 0.04・18.7844) / 0.96 = 0.8741 From Eq. (3), activity coefficient of solvent mixture g mix,solvent is calculated. g mix,solvent = 0.9332・0.6 + 0.8741・0.4 = 0.9096 Total activity coefficients for each volatile component are gained from Eq. (7) as g1 = 1.0427・0.9096・0.7122・0.96 / 0.576 = 1.1257 g2 = 1.3692・0.9096・0.2878・0.96 / 0.384 = 0.8961.
Vapor pressures for each volatile component is calculated from Antoine equation. Antoine constants for methanol and water are A1 = 8.07919、B1 = 1581.341、C1 = 239.65 A2 = 8.02754、B2 = 1705.616、C2 = 231.405. Equilibrium temperature can be determined by bubble point calculation as 72.58 ℃. Then vapor pressure of methanol is P1 = 10 ( 8.07919 - 1581.341 / (72.58 + 239.65) ) = 1034.01 mmHg and that of water is P2 = 10 ( 8.02754 - 1705.616 / (72.58 + 231.405) ) = 261.03 mmHg. Therefore, partial pressures of methanol and water are p1 = 1034.01・1.1257・0.576 = 670.46 mmHg p2 = 261.03・0.8961・0.384 = 89.82 mmHg. Total pressure is then π = p1 + p2 = 760.28 mmHg. Vapor compositions for the components: y1, y2 are y1 = p1 /π = 670.46 / 760.28 = 0.882, y2 = 0.118. Observed bubbling point is 72.6 ℃、vapor phase composition of methanol 0.884mole fraction.. Absolute errors are 0.02 ℃ and 0.002 which are excellent accuracies. |
© 2003-2005. Shuzo Ohe